Answer:
Mass of each electron\[({{m}_{e}})=9.1\times {{10}^{28}}g\] No. of electrons \[(n)=6.023\times {{10}^{23}}\] Total mass of electrons \[=n\times {{m}_{e}}\] \[=6.023\times {{10}^{23}}\times 9.1\times {{10}^{28}}=\text{ }54.8\times {{10}^{5}}g\]
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