Answer:
1 Faraday = 96500 coulombs __________(1) Let the number of electrons be \[x\]. \[\Rightarrow \] 1 Faraday \[=x\times \]charge on each electron _________ (2) Substituting (a) in (b), we get \[\Rightarrow \]\[96500\text{ }C=x\times \] Charge on each electron \[\Rightarrow \]\[96500\text{ }C=x\times 1.6\times {{10}^{19}}C\] (Q Charge on each electron\[=1.6\times {{10}^{19}}C\]) \[\Rightarrow \]\[x=\frac{96500}{1.6\times {{10}^{-19}}}=6.03\times {{10}^{23}}\]electrons Thus, the charge of \[6.03\times {{10}^{23}}\] electrons equal to 1 Faraday.
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