A) 28
B) 44
C) 72
D) 99
Correct Answer: C
Solution :
The valency of M in is +3 hence, the formula of the oxide of element M is \[{{\text{M}}_{\text{2}}}{{\text{O}}_{\text{3}}}\]. Mass of element M in\[\text{MC}{{\text{l}}_{\text{3}}}\text{=118}\text{.5-3(35}\text{.5)=12}\] Molecular mass of \[{{\text{M}}_{\text{2}}}{{\text{O}}_{\text{3}}}=(2\times 12)+(3\times 16)=72\]You need to login to perform this action.
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