A) 10?4
B) 3 ´ 10?4
C) 5 ´ 10?4
D) 6 ´ 10?4
Correct Answer: C
Solution :
\[{{B}_{1}}=4\times {{10}^{-4}}T\] \[{{B}_{2}}={{10}^{-7}}\times \frac{2\times 30}{2\times {{10}^{-2}}}\]\[=3\times {{10}^{-4}}T\] \ \[{{B}_{\text{net}}}=\sqrt{B_{1}^{2}+B_{2}^{2}}\]\[=5\times {{10}^{-4}}T\]You need to login to perform this action.
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