A) 0.2 A
B) 0.4A
C) 4A
D) 40A
Correct Answer: B
Solution :
Magnetic field at the centre of circular loop \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{2\pi i}{r}\Rightarrow 0.5\times {{10}^{-5}}=\frac{{{10}^{-7}}\times 2\times 3.14\times i}{5\times {{10}^{-2}}}\] i = 0.4 AYou need to login to perform this action.
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