A) 1 and 2 \[s{{p}^{2}};\] 3 and 4 \[s{{p}^{3}}\]
B) 1 and 2 \[s{{p}^{2}};\] 3 and 4 \[sp\]
C) 1, 2, 3 and 4 \[sp\]
D) 1, 2 \[s{{p}^{3}};\] 3, 4 \[s{{p}^{2}}\]
Correct Answer: A
Solution :
\[\underset{\,\,\,s{{p}^{2}}\,\,\,\,\,\,s{{p}^{2}}}{\mathop{Br-\overset{1}{\mathop{CH=}}\,\overset{2}{\mathop{CH}}\,-Br}}\,\,\underset{\text{Catalyst}}{\mathop{\xrightarrow{{{H}_{2}}}}}\,Br-\underset{s{{p}^{3}}}{\overset{3\,\,\,\,\,}{\mathop{C{{H}_{2}}}}}\,-\underset{s{{p}^{3}}}{\mathop{\overset{4\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,-Br\]You need to login to perform this action.
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