A) (ii) and (iv)
B) (i) and (iv)
C) (ii) and (iii)
D) (ii)
Correct Answer: D
Solution :
(i) \[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{2}}}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{2}}}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\] only \[s{{p}^{3}}\] hybridized carbon (ii) \[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\] Both \[s{{p}^{2}}\] and \[s{{p}^{3}}\] hybridized carbon. (iii) \[\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,\] Only \[s{{p}^{2}}\] hybridized carbon. (iv) \[H-\underset{sp}{\mathop{C}}\,\equiv \underset{sp}{\mathop{C}}\,-H\] Only sp hybridized carbon.You need to login to perform this action.
You will be redirected in
3 sec