A) 2 kg of ice
B) 200 gm of ice
C) 20 gm ice
D) 2 gm of ice
Correct Answer: B
Solution :
Suppose m kg of ice melts then by using \[\underset{(\text{Joules})}{\mathop{W}}\,=\underset{\text{(Joules)}}{\mathop{H}}\,\] Þ \[Mgh=mL\] Þ \[3.5\times 10\times 2000=m\times 3.5\times {{10}^{5}}\] Þ \[m=0.2\,kg=200\,gm\]You need to login to perform this action.
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