A) \[-\frac{5}{3}{}^\circ C\]
B) \[-\frac{5}{2}{}^\circ C\]
C) ? 5°C
D) 0°C
Correct Answer: D
Solution :
\[{{\theta }_{\text{mix}}}=\frac{{{m}_{W}}{{\theta }_{W}}-\frac{{{m}_{\,i}}{{L}_{\,i}}}{{{S}_{W}}}}{{{m}_{\,i}}+{{m}_{W}}}\]\[=\frac{300\times 25-\frac{100\times 80}{1}}{100+300}=-{{1.25}^{o}}C\] Which is not possible. Hence \[{{\theta }_{mix}}={{0}^{o}}C\]You need to login to perform this action.
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