A) 9 mm
B) 4 mm
C) 8 mm
D) 2 mm
Correct Answer: B
Solution :
(b) 4 mm As, \[\frac{{{\varepsilon }_{0}}A}{d}=4\pi {{\varepsilon }_{0}}R\] Or \[\frac{{{\varepsilon }_{0}}\pi {{D}^{2}}}{4d}=4\pi {{\varepsilon }_{0}}R\] Or \[d=\frac{{{D}^{2}}}{16R}=\frac{{{\left( 0.08 \right)}^{2}}}{16\times 0.10}=4\times {{10}^{-3}}m=4\,mm\]You need to login to perform this action.
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