A) 6.25V
B) 3.0V
C) 12.5 V
D) 25V
Correct Answer: C
Solution :
(c) 12.5V Here, \[V=\frac{{{q}_{1}}-{{q}_{2}}}{2C}\] \[=\frac{2.0\times {{10}^{-8}}+1.0\times {{10}^{-8}}}{2\times 1.2\times {{10}^{-9}}}=12.5V\]You need to login to perform this action.
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