Direction: Q.36 to Q.40 |
A dielectric slab is a substance which does not allow the flow of charges through it but permits them to exert electrostatic forces on one another. |
When a dielectric slab is placed between the plates, the field \[{{E}_{0}}\]polarises the dielectric. This induce charge \[-{{Q}_{P}}\]on the upper surface are \[+{{Q}_{P}}\]on the lower surface of the dielectric. These induced charges set up a field \[{{E}_{P}}\]inside the dielectric in the opposite direction of \[{{\overrightarrow{E}}_{0}}\] as shown. |
Read the given passage carefully and give the answer of the following questions. |
A) 10
B) 20
C) 50
D) 100
Correct Answer: B
Solution :
(b) 20 \[K=\frac{Capacitance\text{ }with\text{ }dielectric}{Capacitance\text{ }without\text{ }dielectric}=\frac{80\,\mu F}{4\,\mu F}=20\]You need to login to perform this action.
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