A) \[1/2\]
B) 2
C) \[1/\sqrt{2}\]
D) \[\sqrt{2}\]
Correct Answer: B
Solution :
\[{{F}_{12}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{{{q}^{2}}}{{{a}^{2}}}\] and \[{{F}_{13}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{{{q}^{2}}}{{{(a\sqrt{2})}^{2}}}\]Þ \[\frac{{{F}_{12}}}{{{F}_{13}}}=2\]You need to login to perform this action.
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