A) \[125\ dynes\]
B) \[35\ dynes\]
C) \[25\ dynes\]
D) Zero
Correct Answer: C
Solution :
Net force on B \[{{F}_{net}}=\sqrt{F_{A}^{2}+F_{C}^{2}}\] \[{{F}_{A}}=\frac{15\times 12}{{{\left( 3 \right)}^{2}}}=20\,\,dyne\], \[{{F}_{C}}=\frac{12\times 20}{{{\left( 4 \right)}^{2}}}=15\,\,dyne\] Þ \[{{F}_{net}}=\sqrt{F_{A}^{2}+F_{C}^{2}}=\sqrt{{{(20)}^{2}}+{{(15)}^{2}}}=25\,\,dyne\]You need to login to perform this action.
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