A) 2.5
B) 5.0
C) 10.0
D) 20.0
Correct Answer: B
Solution :
\[({{H}_{2}}S{{O}_{4}})\frac{{{M}_{1}}{{V}_{1}}}{{{n}_{1}}}=\frac{{{M}_{2}}{{V}_{2}}}{{{n}_{2}}}(NaOH)\] \[\frac{1\times {{V}_{1}}}{1}=\frac{1\times 10}{2}\]; \[{{V}_{1}}=5ml\].You need to login to perform this action.
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