A) \[8\sqrt{10}\]
B) \[6\sqrt{10}\]
C) \[4\sqrt{10}\]
D) \[2\sqrt{10}\]
Correct Answer: D
Solution :
[d] From figure, In \[\Delta OCM,\]\[C{{M}^{2}}={{7}^{2}}-{{3}^{2}}=40\] \[\therefore \] \[CM=2\sqrt{10}\,cm\] In \[\Delta AOM\] \[AM=\sqrt{{{13}^{2}}-{{3}^{2}}}=4\sqrt{10}\] Now, \[AC=AM-CM=2\sqrt{10}\,cm\] |
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