A) 6 units
B) 9 units
C) 12 units
D) 15 units
Correct Answer: C
Solution :
[c] From figure, \[P{{T}^{2}}=PA\cdot PB\] \[\Rightarrow \] \[{{(2x)}^{2}}=x\,(18+x)\] \[\Rightarrow \] \[4{{x}^{2}}=x\,(18+x)\] \[\Rightarrow \] \[4x=18+x\]\[\Rightarrow \]\[x=6\] \[\therefore \] \[PT=2\times 6=12\,\text{units}\] |
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