A) \[\sqrt{{{K}_{sp}}}\]
B) \[^{3}\sqrt{{{K}_{sp}}}\]
C) \[^{3}\sqrt{\frac{{{K}_{sp}}}{4}}\]
D) \[\sqrt{8{{K}_{sp}}}\]
Correct Answer: C
Solution :
\[PbC{{l}_{2}}\] ⇌\[\underset{S\,\,}{\mathop{P{{b}^{2+}}}}\,+\underset{S\,\,}{\mathop{2C{{l}^{-}}}}\,\] \[{{K}_{sp}}\]of \[PbC{{l}_{2}}=[P{{b}^{2+}}]\times {{[C{{l}^{-}}]}^{2}}\] ;\[{{K}_{sp}}=S\times {{(2S)}^{2}}\] \[{{K}_{sp}}=S\times 4{{S}^{2}}\]\[=4{{S}^{3}}\]; \[{{S}^{3}}=\frac{{{K}_{sp}}}{4}\]; \[S=\sqrt[3]{\frac{{{K}_{sp}}}{4}}\]You need to login to perform this action.
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