A) \[0.72\times {{10}^{-4}}\,M\]
B) \[1.20\times {{10}^{-2}}\,M\]
C) \[{{80}^{o}}C,\]
D) \[0.5\,M\,HCOOH,\]
Correct Answer: B
Solution :
AgCl ⇌ \[[A{{g}^{+}}]\,\,[C{{l}^{-}}]\] ;\[{{K}_{sp}}=S\times S\] ; \[{{K}_{sp}}={{S}^{2}}\] \[S=\sqrt{{{K}_{sp}}}\]\[=\sqrt{1.44\times {{10}^{-4}}}\] \[=1.20\times {{10}^{-2}}\]M.You need to login to perform this action.
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