A) \[{{(2\tan \theta )}^{1/3}}\]
B) \[{{(2\tan \theta )}^{-1/3}}\]
C) \[{{(2\cot \theta )}^{1/3}}\]
D) \[{{(2\cot \theta )}^{-1/3}}\]
Correct Answer: C
Solution :
In equilibrium \[{{B}_{1}}={{B}_{2}}\tan \theta \] \[\Rightarrow \frac{{{\mu }_{0}}}{4\pi }.\frac{2M}{d_{1}^{3}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{M}{d_{2}^{3}}\tan \theta \] \[\Rightarrow \frac{{{d}_{1}}}{{{d}_{2}}}={{\left( 2\cot \theta \right)}^{1/3}}\]You need to login to perform this action.
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