A) \[\frac{{{\mu }_{0}}}{4\pi }\frac{M}{{{d}^{3}}}\]
B) \[\frac{{{\mu }_{0}}}{4\pi }\frac{M\sqrt{2}}{{{d}^{3}}}\]
C) \[\frac{{{\mu }_{0}}}{4\pi }\frac{2\sqrt{2}M}{{{d}^{3}}}\]
D) \[\frac{{{\mu }_{0}}}{4\pi }\frac{2M}{{{d}^{3}}}\]
Correct Answer: C
Solution :
Resultant magnetic moment of the two magnets is \[{{M}_{net}}=\sqrt{{{M}^{2}}+{{M}^{2}}}=\sqrt{2}M\] Imagine a short magnet lying along OP with magnetic moment equal to \[M\sqrt{2}\]. Thus point P lies on the axial line of the magnet. \[\therefore \]Magnitude of magnetic field at P is given by \[B=\frac{{{\mu }_{0}}}{4\pi }.\frac{2\sqrt{2}M}{{{d}^{3}}}\]You need to login to perform this action.
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