• # question_answer Amongest following the lowest degree of paramagnetism per mole of the compound at 298 K will be shown by A) $MnS{{O}_{4}}.4{{H}_{2}}O$ B) $CuS{{O}_{4}}.5{{H}_{2}}O$ C) $FeS{{O}_{4}}.6{{H}_{2}}O$ D) $FeS{{O}_{4}}.5{{H}_{2}}O$

$CuS{{O}_{4}}.5{{H}_{2}}O$ Because it has only one unpaired electrons.