JEE Main & Advanced Chemistry The d-and f-Block Elements Question Bank Critical Thinking

  • question_answer Amongest following the lowest degree of paramagnetism per mole of the compound at 298 K will be shown by

    A) \[MnS{{O}_{4}}.4{{H}_{2}}O\]

    B) \[CuS{{O}_{4}}.5{{H}_{2}}O\]

    C) \[FeS{{O}_{4}}.6{{H}_{2}}O\]

    D) \[FeS{{O}_{4}}.5{{H}_{2}}O\]

    Correct Answer: B

    Solution :

    \[CuS{{O}_{4}}.5{{H}_{2}}O\] Because it has only one unpaired electrons.

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