A) + 250 kJ
B) ? 250 kJ
C) + 125 kJ
D) ? 125 kJ
Correct Answer: D
Solution :
\[C{{H}_{2}}=C{{H}_{2(g)}}+{{H}_{2(g)}}\to {{H}_{3}}C-C{{H}_{3(g)}}\] \[414\times 4=1656\] \[414\times 6=2484\] \[615\times 1=615\] \[347\times 1=\,\,347\] \[435\times 1\,\,\,=\,\underset{\overline{\underline{2706}}}{\mathop{435}}\,\] 2831 \[\Delta H=2706-2831=-125\,kJ\]You need to login to perform this action.
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