A) 321 Hz
B) 298 Hz
C) 289 Hz
D) 280 Hz
Correct Answer: B
Solution :
Here \[{{v}_{A}}=72\,km/hr=20m/\sec \] \[{{v}_{B}}=36km/hr=10m/\sec \] \[n'=n\left( \frac{v+{{v}_{B}}\cos {{45}^{o}}}{v-{{v}_{A}}\cos {{45}^{o}}} \right)\] \[\Rightarrow \] \[n'=280\,\left( \frac{340+10/\sqrt{2}}{340-20/\sqrt{2}} \right)=298\,Hz\]You need to login to perform this action.
You will be redirected in
3 sec