A) 2
B) 4
C) 6
D) 8
Correct Answer: B
Solution :
For observer note of \[B\] will not change due to zero relative motion. Observed frequency of sound produced by A = \[660\frac{(330-30)}{330}=600\,Hz\] \[\therefore \] No. of beats = 600 ? 596 = 4You need to login to perform this action.
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