A) \[\sqrt{gL}\]
B) \[\sqrt{gx}\]
C) \[gL\]
D) \[gx\]
Correct Answer: B
Solution :
Velocity \[v=\sqrt{\frac{T}{m}}\]; where \[T=\]weight of part of rope hanging below the point under consideration \[=\left( \frac{M}{L} \right)xg\] Þ \[v=\sqrt{\frac{\left( \frac{M}{L} \right)xg}{\left( \frac{M}{L} \right)}}=\sqrt{xg}\].You need to login to perform this action.
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