A) 500 Hz
B) 1000 Hz
C) 2000 Hz
D) 4000 Hz
Correct Answer: B
Solution :
When the piston is moved through a distance of 8.75cm, the path difference produced is \[2\times 8.75\,cm=17.5\,cm\]. This must be equal to\[\frac{\lambda }{2}\] for maximum to change to minimum. \ \[\frac{\lambda }{2}=17.5\]cm Þ \[\lambda =35cm=0.35m\] So, \[v=n\lambda \]Þ \[n=\frac{v}{\lambda }=\frac{350}{0.35}=1000Hz\]You need to login to perform this action.
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