A) 1 : 1
B) 2 : 1
C) 1 : 2
D) 4 : 1
Correct Answer: D
Solution :
\[l=\frac{FL}{AY}\]\ \[l\propto \frac{1}{{{r}^{2}}}\] (F, L and Y are constant) \[\frac{{{l}_{1}}}{{{l}_{2}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{2}}={{(2)}^{2}}=4\]You need to login to perform this action.
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