JEE Main & Advanced Physics Elasticity Question Bank Critical Thinking

  • question_answer
    A particle of mass m is under the influence of a force F which varies with the displacement x according to the relation \[F=-kx+{{F}_{0}}\]in which k and \[{{F}_{0}}\] are constants. The particle when disturbed will oscillate            [UPSEAT 2001]

    A) about \[x=0,\,\text{with }\omega \ne \sqrt{k/m}\]

    B)             about \[x=0,\,\text{with }\omega =\sqrt{k/m}\]

    C)             about \[x={{F}_{0}}/k\,\,\text{with }\omega =\sqrt{k/m}\]

    D)             about \[x={{F}_{0}}\text{/}k\,\text{with }\omega \ne \sqrt{k/m}\]

    Correct Answer: C

    Solution :

                Restoring force is zero at mean position             \[F=-Kx+{{F}_{0}}\]Þ \[0=-Kx+{{F}_{0}}\]Þ\[x=\frac{{{F}_{0}}}{K}\] i.e. the particle will oscillate about \[x=\frac{{{F}_{0}}}{K}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner