A) 12.22
B) 24.42
C) Negative
D) That the given values are not correct
Correct Answer: A
Solution :
Power consumed by heater is 110 W so by using \[P=\frac{{{V}^{2}}}{R}\] \[110=\frac{{{V}^{2}}}{110}\,\,\Rightarrow \,V=110\,V.\] Also from figure \[{{i}_{1}}=\frac{110}{110}=1A\] and \[i=\frac{110}{11}=10\,A.\] So \[{{i}_{2}}=10-1=9\,A\] Applying Ohms law for resistance R, V = iR \[\Rightarrow \,\,110=9\times R\]Þ \[R=12.22\,\Omega \]You need to login to perform this action.
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