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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Critical Thinking

  • question_answer
    A 500 W heating unit is designed to operate from a 115 volt line. If the line voltage drops to 110 volt, the percentage drop in heat output will be                            [ISM Dhanbad 1994]

    A)                    10.20%                            

    B)                    8.1%

    C)                    8.6%                                 

    D)                    7.6%

    Correct Answer: C

    Solution :

                       \[{{P}_{consumed}}={{\left( \frac{{{V}_{A}}}{{{V}_{R}}} \right)}^{2}}\times {{P}_{R}}={{\left( \frac{110}{115} \right)}^{2}}\times 500=457.46\,\,W\] So, percentage drop in power output \[=\frac{(500-457.46)}{500}\times 100=8.6%\]


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