A) \[\frac{\sin x+x\cos x}{2\sqrt{x\sin x}}\]
B) \[\frac{\sin x+x\cos x}{\sqrt{x\sin x}}\]
C) \[\frac{x\sin x+\cos x}{\sqrt{2\sin x}}\]
D) \[\frac{\sin x+x\cos x}{2\sqrt{x\sin x}}\]
Correct Answer: A
Solution :
Let \[{{y}^{2}}=x\sin x\Rightarrow 2y\frac{dy}{dx}=\sin x+x\cos x\] \[\therefore \frac{dy}{dx}=\frac{[\sin x+x\cos x]}{2\sqrt{x\sin x}}\].You need to login to perform this action.
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