A) \[4\cos \text{ec 2}x.\cot 2x\]
B) \[-4\cos \text{ec 2}x.\cot 2x\]
C) \[-4\cos \text{ec }x.\cot 2x\]
D) None of these
Correct Answer: B
Solution :
\[\frac{d}{dx}[\sqrt{{{\sec }^{2}}x+\text{cose}{{\text{c}}^{2}}x}]=\frac{d}{dx}\left[ \sqrt{\left( \frac{1}{{{\cos }^{2}}x}+\frac{1}{{{\sin }^{2}}x} \right)} \right]\] \[=\frac{d}{dx}[2\,\text{cosec}2x]=-4\,\text{cosec}2x\cot 2x\].You need to login to perform this action.
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