A) \[\sec x\]
B) \[\cos \text{ec}\,x\]
C) \[\cos \text{ec}\frac{x}{2}\]
D) \[\sec \frac{x}{2}\]
Correct Answer: B
Solution :
\[\frac{d}{dx}\left[ \log \sqrt{\frac{1-\cos x}{1+\cos x}} \right]=\frac{d}{dx}\left[ \log \left( \tan \frac{x}{2} \right) \right]=\text{cosec}\,x\].You need to login to perform this action.
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