A) \[-\frac{1}{2}\]
B) 0
C) \[\frac{1}{2}\]
D) 1
Correct Answer: C
Solution :
\[\frac{d}{dx}\left[ {{\tan }^{-1}}\sqrt{\frac{1-\cos x}{1+\cos x}} \right]=\frac{d}{dx}\left[ {{\tan }^{-1}}\tan \frac{x}{2} \right]=\frac{1}{2}\].You need to login to perform this action.
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