A) 1, 3
B) 1, ? 3
C) ? 1, 3
D) None of these
Correct Answer: D
Solution :
\[f(x)={{x}^{2}}-3x\]and \[f'(x)=2x-3\] But \[f(x)=f'(x)\Rightarrow {{x}^{2}}-3x=2x-3\]Þ \[{{x}^{2}}-5x+3=0\] \[\therefore x=\frac{5\pm \sqrt{25-12}}{2}=\frac{5\pm \sqrt{13}}{2}\].You need to login to perform this action.
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