A) 1
B) 2
C) 3
D) ? 3
Correct Answer: C
Solution :
Here \[f'(x)=m=1\]Þ\[f'(0)=m=1\] and \[f(0)=c=1\]. Therefore \[\therefore \frac{dy}{dx}=\frac{3}{2}{{(x{{\cot }^{3}}x)}^{1/2}}[{{\cot }^{3}}x+3x{{\cot }^{2}}x(-\text{cose}{{\text{c}}^{2}}x)]\].You need to login to perform this action.
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