A) 0
B) 1
C) ? 1
D) ? 2
Correct Answer: D
Solution :
\[\frac{d}{dx}[{{\tan }^{-1}}(\cot x)+{{\cot }^{-1}}(\tan x)]\] =\[\frac{1(-\text{cose}{{\text{c}}^{2}}x)}{1+{{\cot }^{2}}x}-\frac{1({{\sec }^{2}}x)}{1+{{\tan }^{2}}x}=-1-1=-2\].You need to login to perform this action.
You will be redirected in
3 sec