A) \[{{e}^{ax}}[a\cos (bx+c)-b\sin (bx+c)]\]
B) \[{{e}^{ax}}[a\sin (bx+c)-b\cos (bx+c)]\]
C) \[{{e}^{ax}}[\cos (bx+c)-\sin (bx+c)]\]
D) None of these
Correct Answer: A
Solution :
\[\frac{d}{dx}[{{e}^{ax}}\cos (bx+c)]\]=\[\frac{dx}{dt}=-2\sin t+2\sin 2t\] =\[{{e}^{ax}}[a\cos (bx+c)-b\sin (bx+c)]\].You need to login to perform this action.
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