Answer:
According to Einstein?s photoelectric equation, \[{{K}_{\max }}=\frac{1}{2}m\upsilon _{\max }^{2}=hv-{{W}_{0}}\] \[\therefore \] \[\upsilon _{\max }^{2}=\left( \frac{2h}{m} \right)v-\frac{2{{W}_{0}}}{m}\] Thus the graph of \[\upsilon _{\max }^{2}\upsilon s.v\]is a straight equation, line. Clearly, Slope of graph, \[\frac{2h}{m}=\frac{l}{n}\] Intercept on \[\upsilon _{\max }^{2}\]axis, \[\frac{2{{W}_{0}}}{m}=l\] \[\therefore \]Planck?s constant, \[h=\frac{lm}{2n}.\] Work function, \[{{W}_{0}}=\frac{ml}{2}\]
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