Answer:
The graph is shown in Fig. (i) Metal a has a higher work function \[(W_{0}^{'}=hv_{0}^{'})\]because \[v_{0}^{,}>{{v}_{0}}.\] (ii) As \[e{{V}_{0}}=hv-{{W}_{0}}\] or \[{{V}_{0}}=\left( \frac{h}{e} \right)v-\frac{{{W}_{0}}}{e}\] \[\therefore \] Slope of \[{{V}_{0}}-v\]graph \[=\frac{h}{e}\] (iii) Intercept of graph A on the potential ? axis \[=-\frac{W_{0}^{'}}{e}=-\frac{hv_{0}^{'}}{e}\]
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