A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{3}+{{\tan }^{-1}}\left( \frac{\sqrt{3}}{2} \right)\]
C) \[\frac{2\pi }{3}\]
D) \[{{\tan }^{-1}}\left( \frac{\sqrt{3}}{2} \right)\]
Correct Answer: B
Solution :
\[\theta =\frac{\pi }{3}+\alpha \] where \[\tan \alpha =\frac{1}{2}\tan \frac{\pi }{3}\] Þ \[\alpha ={{\tan }^{-1}}\sqrt{3}/2\] so, \[\theta =\frac{\pi }{3}+{{\tan }^{-1}}\sqrt{3}/2\]You need to login to perform this action.
You will be redirected in
3 sec