A) \[ql\]
B) \[2ql\]
C) \[\sqrt{3}ql\]
D) \[4ql\]
Correct Answer: C
Solution :
\[{{p}_{net}}=\sqrt{{{p}^{2}}+{{p}^{2}}+2pp\cos 60{}^\circ }=\sqrt{3}p=\sqrt{3}\,ql\] (Q p = ql)You need to login to perform this action.
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