A) Zero
B) \[\left( \frac{-qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\,\sqrt{2}a\]
C) \[\left( \frac{qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\,\frac{a}{\sqrt{2}}\]
D) \[\left( \frac{qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\,\sqrt{2}a\]
Correct Answer: A
Solution :
Since A and B are at equal potential so potential difference between A and B is zero. Hence \[W=Q.\Delta V=\text{ }0\]You need to login to perform this action.
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