A) \[8\,{{q}_{2}}\]
B) \[8\,{{q}_{1}}\]
C) \[6{{q}_{2}}\]
D) \[6{{q}_{1}}\]
Correct Answer: A
Solution :
Change in potential energy \[(\Delta U)\text{ }={{U}_{f}}{{U}_{i}}\] Þ \[\Delta U=\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ \left( \frac{{{q}_{1}}{{q}_{3}}}{0.4}+\frac{{{q}_{2}}{{q}_{3}}}{0.1} \right)-\left( \frac{{{q}_{1}}{{q}_{3}}}{0.4}+\frac{{{q}_{2}}{{q}_{3}}}{0.5} \right) \right]\] Þ \[\Delta U=\frac{1}{4\pi {{\varepsilon }_{0}}}[8{{q}_{2}}{{q}_{3}}]=\frac{{{q}_{3}}}{4\pi {{\varepsilon }_{0}}}(8{{q}_{2}})\] \[\therefore \,\,\,k=\text{ }8{{q}_{2}}\]You need to login to perform this action.
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