A) \[2\times {{10}^{-2}}\]
B) \[2\times {{10}^{-3}}\]
C) \[2\times {{10}^{-4}}\]
D) \[2\times {{10}^{-5}}\]
Correct Answer: B
Solution :
\[E=\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{q}{{{r}^{2}}}=9\times {{10}^{9}}\times \frac{q}{{{r}^{2}}}\] \ \[q=\frac{E\times {{r}^{2}}}{9\times {{10}^{9}}}=\frac{3\times {{10}^{6}}\times {{(2.5)}^{2}}}{9\times {{10}^{9}}}=2.0833\times {{10}^{-3}}\] q should be less than 2.0833 ´ 10?3. In the given set of options 2 ´ 10?3 is the maximum charge which is smaller than 2.0833 ´ 10?3.
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