A) At a distance of \[5\,cm\]from \[25\mu C\]
B) At a distance of \[5\,cm\]from \[36\mu C\]
C) At a distance of \[10\,cm\]from \[25\mu C\]
D) At a distance of \[11\,cm\]from \[36\mu C\]
Correct Answer: A
Solution :
Suppose electric field is zero at point N in the figure then At \[N\left| {{E}_{1}} \right|=\left| {{E}_{2}} \right|\] which gives \[{{x}_{1}}=\frac{x}{\sqrt{\frac{{{Q}_{2}}}{{{Q}_{1}}}}+1}=\frac{11}{\sqrt{\frac{36}{25}}+1}=5cm\]You need to login to perform this action.
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