A) \[\frac{1}{3}V\]
B) \[\frac{2}{3}V\]
C) \[\frac{3}{2}V\]
D) \[3V\]
Correct Answer: B
Solution :
Potential inside the sphere will be same as that on its surface i.e. \[V={{V}_{surface}}=\frac{q}{10}stat\,volt\], \[{{V}_{out}}=\frac{q}{15}stat\,volt\] \\[\frac{{{V}_{out}}}{V}=\frac{2}{3}\] Þ \[{{V}_{out}}=\frac{2}{3}V\]You need to login to perform this action.
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