A) Zero
B) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\]
C) \[\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{q}{d}\]
D) \[\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{2q}{{{d}^{2}}}\]
Correct Answer: A
Solution :
Potential at mid point \[O,\,\,\,V=\frac{kq}{d}+\frac{k(-q)}{d}=0\]You need to login to perform this action.
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