A) \[2.0\times {{10}^{-6}}m\]
B) \[1.7\times {{10}^{-6}}m\]
C) \[1.4\times {{10}^{-6}}m\]
D) \[1.1\times {{10}^{-6}}m\]
Correct Answer: B
Solution :
In equilibrium QE = mg Þ \[Q.\frac{V}{d}=mg=\left( \frac{4}{3}\pi {{r}^{3}}\rho \right)\,g\] Þ \[2\times 1.6\times {{10}^{-19}}\times \frac{12000}{2\times {{10}^{-2}}}=\frac{4}{3}\pi {{r}^{3}}\times 900\times 10\] Þ\[~r=\text{ }1.7\times {{10}^{6}}m\]You need to login to perform this action.
You will be redirected in
3 sec